質問 13-3. R, p_2/p_1 の値をもとめよ。
- R=0.107 p1/p2=1.37
- R=0.1157 p1/p2=1.368
- R = 0.94 p_2 - 1p_2 / p_1 = 90/71
- p2/p1=1.38 R=0.114
- (8+6(p2/p1))/(7+5.5(p2/p1))=R
- R=0.1189,p2/p1=1.3866
- p2/p1=1.3848 R=0.115785
- R=0.107 p1/p2=1.368
- R=0.107 p1/p2=1.368
- R=0.1157,p2/p1=1.3847
- R=0.1158,p2/p1=1.38
- R=(p1+(1/2)p2)/(7p1+(11/2)p2),p2/p1=?